How fast was the arrow shot?
February 12, 2010 by Bowhunter
Filed under Archery Set
bud the spud asked:
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. You find the arrow stuck in the ground 57.0 m away, making a 3.00 degree angle with the ground.
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. You find the arrow stuck in the ground 57.0 m away, making a 3.00 degree angle with the ground.
How fast was the arrow shot?
please help! show set up! Thank you so much!!!!
Titanium Rings
Bowhunting
You need an additional information: the vertical height of the arrow from the ground when it was shot. From this we can calculate the time it took the arrow to reach the ground: t = sqrt(2d/g), where d = vertical height of the arrow from the ground when it was shot and g = 9.8 m/s^2.
Then you just divide 57.0 m by the t that you got to give you the speed of the arrow.
Hope this helps.
teddy boy
Video Games
At first I thought you needed the height from which the arrow was loosed.
Then I did the math.
The height of the flight path curve is given by
1) y = [-g/(2V²)]*x² + Hi
differentiating with respect to x,
2) y’ = [-g/V²]*x ? V² = [-g/y']*x = [-9.8/tan(-3°)]*57 = 10658.7
V = 103.2 m/s
Using this result in eq 1),
Hi = 1.493 m